1/2(x-4)^2+5=-13

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Solution for 1/2(x-4)^2+5=-13 equation: 



1/2(x-4)^2+5=-13

We move all terms to the left:

1/2(x-4)^2+5-(-13)=0



Domain of the equation: 2(x-4)^2!=0

x∈R



We add all the numbers together, and all the variables

1/2(x-4)^2+18=0

We multiply all the terms by the denominator


18*2(x-4)^2+1=0

Wy multiply elements

36x(x+1=0

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